In the given figure P is 300 km eastward of O and Q is 400 kms North of Q, R is exactly in the middle of Q and P The distance between Q and R is ______________.
A
250 kms
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B
250√2kms
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C
300 kms
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D
350 kms
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E
None of these
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Solution
The correct option is A 250 kms PQ = OP2+OQ2−−−−−−−−−−√OP2+OQ2 =(300)2+(400)2−−−−−−−−−−−−√=1002(32+42)−−−−−−−−−−−√(300)2+(400)2=1002(32+42) =1002×52−−−−−−−−√=(100×5)=1002×52=(100×5) i.e. 500 km R being in the midway of PQ so QR = 250 kms