In the given figure PA = 2 cm and PB = 8 cm, the value of PT is equal to
A
3 cm
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B
4 cm
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C
5 cm
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D
6 cm
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Solution
The correct option is B 4 cm If a secant AB and tangent at the point T of a circle intersect at a point P outside the circle then PA×PB=PT2 Substituting the value we get 2×8=PT2 PT2=16 PT=4cm