In the given figure PA = 2 cm and PB = 8 cm, the value of PT is equal to

3 cm

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4 cm

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5 cm

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6 cm

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Solution

The correct option is B 4 cm
If a secant AB and tangent at the point T of a circle intersect at a point P outside the circle then $P A \times P B = P T^{2}$
Substituting the value we get
$2 \times 8 = P T^{2}$
$P T^{2} = 16$
$P T = 4 c m$

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In the given figure PA = 2 cm and PB = 8 cm, the value of PT is equal to

The correct option is B 4 cmIf a secant AB and tangent at the point T of a circle intersect at a point P outside the circle then PA×PB=PT2 Substituting the value we get 2×8=PT2 PT2=16 PT=4 cm

The correct option is B 4 cm
If a secant AB and tangent at the point T of a circle intersect at a point P outside the circle then $P A \times P B = P T^{2}$
Substituting the value we get
$2 \times 8 = P T^{2}$
$P T^{2} = 16$
$P T = 4 c m$