In the given figure PA = 3 cm and PB = 6 cm, the value of PT is equal to
A
2√2cm
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B
3√2cm
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C
2√3cm
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D
3√3cm
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Solution
The correct option is B3√2cm If a secant AB and tangent at the point T of a circle intersect at a point P outside the circle then PA×PB=PT2 Substituting the value we get 3×6=PT2 PT2=18 PT=3√2cm