Question

In the given figure PA = 3 cm and PT = 4 cm, the value of PB is equal to

• A. $\frac{8}{3}$ cm
• B. $\frac{16}{3}$ cm
• C. $\frac{16}{9}$ cm
• D. $\frac{4}{9}$ cm

Answer 1

The correct option is B $\frac{16}{3}$ cm

If a secant AB and tangent at the point T of a circle intersect at a point P outside the circle then $PA\times PB=P{T}^2$
Substituting the value we get
$3\times PB=4^2$
$PB=\frac{4^2}{3}$
$PB=\frac{16}{3}$ cm