In the given figure PA = 7 cm and PB = 28 cm, the value of PT is equal to _______.
[2 Marks]

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Solution

If a secant AB and tangent at the point T of a circle intersect at a point P outside the circle then $P A \times P B = P T^{2}$ [1 Mark]
Substituting the value we get
$7 \times 28 = P T^{2}$
$P T^{2} = 196$
$P T = 14 c m$ [1 Mark]

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