In the given figure PA $= 9$ , PB $= 4$ and PC $= 12$ . Find PD.

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Solution

Fact: If P is point of intersection of any two chords AB and CD of a circle then,

$P A \cdot P B = P C \cdot P D$

$\Rightarrow 9 \cdot 4 = 12 \cdot P D$

$\Rightarrow P D = \frac{36}{12}$

$∴ P D = 3$

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In the given figure PA=9, PB=4 and PC=12. Find PD.

Fact: If P is point of intersection of any two chords AB and CD of a circle then,PA⋅PB=PC⋅PD⇒9⋅4=12⋅PD⇒PD=3612∴PD=3

In the given figure PA $= 9$ , PB $= 4$ and PC $= 12$ . Find PD.

Fact: If P is point of intersection of any two chords AB and CD of a circle then,

$P A \cdot P B = P C \cdot P D$

$\Rightarrow 9 \cdot 4 = 12 \cdot P D$

$\Rightarrow P D = \frac{36}{12}$

$∴ P D = 3$