In the given figure, PA and PB are tangents from an external point P to a circle with centre O. LN touches the circle at M. Prove that PL + ML = PN + MN.
[2 Marks]
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Solution
PA = PB [the tangents drawn from an external point to a circle are equal ----(1) (1 mark)
PL + AL = PN + BN
AL = ML & BN = MN [same as (1)] (0.5 mark)
From above steps,
Thus, PL + ML = PN + MN (0.5 mark)