In the given figure PA and PB are tangents to a circle with centre O - If - APB -2 x -3- and - AOB -3 x -7- then find the value of x-

Sum of opposite angles in a quadilateral = 180^∘ ∠ APB + ∠ AOB = 180^∘ (2x+3)+(3x+7) = 180^∘ 5x+10 = 180^∘ 5x = 170^∘ x = 34 ...

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In the given ...

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In the given figure PA and PB are tangents to a circle with centre O. If $∠ A P B = (2 x + 3)^{\circ}$ and $∠ A O B = (3 x + 7)^{\circ}$ , then find the value of x.

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∠ A P B = 50^{\circ}

∠ A O B

If PA and PB are two tangents to a circle with centre O such that $∠$ AOB = $110^{o}$ then $∠$ APB is equal to

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∠ A P B = 60^{\circ},

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