Question

In the given figure, $PA$ $\perp$ $AB$, $QB$ $\perp$ $AB$ and $\Delta$ $OAP$ $\cong \Delta$ $OBQ$, then:

• A. $PA$ $=$ $OB$
• B. $AP$ $=$ $QB$
• C. $OP$ $=$ $BQ$
• D. $OA$ $=$ $OQ$

Answer 1

Answer: (B)

$AP$ $=$ $QB$

It is given that $\Delta OAP$ $\cong$ $\Delta OBQ$ both triangles are congruent.

That is by CPCT rule, corresponding parts of congruent triangles are equal.

Then, $OA=OQ,AP=QB,OP=OQ$, $\angle O=\angle O$, $\angle A=\angle B$ and $\angle P=\angle Q$.

So, option $B$ is correct.