wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the given figure, point S is any point on side QR of PQR Prove that : PQ + QR + RP > 2PS

Open in App
Solution

In △PQS
PQ + QS > PS ...(1)
(Sum of two sides of a traingle is greater than the third side)
In △PRS
RP + RS > PS ...(2)
​ (Sum of two sides of a traingle is greater than the third side)
Adding (1) and (2), we get
PQ + QS + RP + RS > PS + PS
⇒ PQ + QR + RP > 2PS

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
"If Two Angles of a Triangle Are Unequal Then the Side Opposite to the Greater Angle Is Greater
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon