Given, ∠4 = ∠5,
∠2 = ∠5 ..........(1)
[Alternate interior angles]. [1 Mark]
∠2 = ∠3 ............(2)
[Both are bisected so they are equal and half of PQC].
From (1) and (2),
∠4 = ∠5 = ∠3,
Since all the angles are equal in the ΔQBC it is an equilateral triangle and hence each angle is 60∘.
[1 Mark]
∠4 = ∠5 = ∠3 = 60∘
∠1= ∠4= 60∘ [Corresponding angles]. [ 1 Mark]