Question 3 In the given figure, PQ is a mirror, AB is the incident ray and BC is the reflected ray. If ∠ABC=46∘, then ∠ABP is equal to (a) 44∘ (b) 67∘ (c) 13∘ (d) 62∘
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Solution
We know that the angle of incidence is always equal to the angle of reflection. ∠ABP=∠CBQ i.e. a = b Now sum of all the angles on a straight line is 180∘. ∴a+46∘+b=180∘ ⇒2a=180∘−46∘⇒2a=134∘⇒a=134∘2=67∘∴∠ABP=67∘