In fig- PQ is parallel to MN- If KP - PM -4-13 and KN -20-4 cm- Find KQ -2 MARKS-

Concept: 1 Mark Application: 1 Mark In Δ KMN, we have PQ ∥ MN ∴KP/PM = KQ/QN [Basic proportionality Theorem] ⇒KP/PM = KQ/KN KQ ⇒4/13 = KQ/20.4 KQ ⇒ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Criteria for Similarity of Triangles

In fig., PQ i...

Question

In fig., PQ is parallel to MN. If $\frac{K P}{P M} = \frac{4}{13}$ and KN = 20.4 cm. Find KQ [2 MARKS]

Open in App

Solution

Concept: 1 Mark
Application: 1 Mark

In $Δ K M N$ , we have

$P Q ∥ M N$

$∴ \frac{K P}{P M} = \frac{K Q}{Q N}$ [Basic proportionality Theorem]

$\Rightarrow \frac{K P}{P M} = \frac{K Q}{K N - K Q}$

$\Rightarrow \frac{4}{13} = \frac{K Q}{20.4 - K Q}$

$\Rightarrow 4 (20.4 - K Q) = 13 K Q$

$\Rightarrow 81.6 - 4 K Q = 13 K Q$

$\Rightarrow 17 K Q = 81.6$

$\Rightarrow K Q = \frac{81.6}{17} = 4.8 c m$

Suggest Corrections

215

Similar questions

Q. In given figure PQ is parallel to MN. If

\frac{K P}{P M} = \frac{4}{13}

and

K N = 20.4 c m

Find KQ,

In fig., PQ is parallel to MN. If $\frac{K P}{P M} = \frac{4}{13}$ and KN = 20.4 cm. Find KQ

In fig., If PQ $∥$ BC and PR $∥$ CD. Prove that $\frac{A R}{A D}$ = $\frac{A Q}{A B}$ . [4 MARKS]

Q. In

Δ

PQR, MN is parallel to QR and

\frac{P M}{M Q} = \frac{2}{3}

. Find

\frac{M N}{Q R}

P Q R S

is a trapezium. Given that segment

P Q ∥

segment

M N ∥

segment

S R .

P M = 8, M S = 10

and

N R = 5,

then find

Q N .

Join BYJU'S Learning Program

In fig., PQ is parallel to MN. If KPPM=413 and KN = 20.4 cm. Find KQ [2 MARKS]

Concept: 1 Mark Application: 1 Mark In ΔKMN, we have PQ∥MN ∴KPPM=KQQN [Basic proportionality Theorem] ⇒KPPM=KQKN−KQ ⇒413=KQ20.4−KQ ⇒4(20.4−KQ)=13 KQ ⇒81.6−4 KQ=13 KQ ⇒17 KQ=81.6 ⇒KQ=81.617=4.8 cm

In fig., PQ is parallel to MN. If $\frac{K P}{P M} = \frac{4}{13}$ and KN = 20.4 cm. Find KQ [2 MARKS]