In the given figure, PQ is the tangent of the circle. Line segment PR intersects the circle at N and R. PQ = 15 cm, PR = 25 cm, find PN:

15 cm

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10 cm

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9 cm

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6 cm

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Solution

The correct option is C 9 cm
$P N \times P R = (P Q^{2}) P N \times 25 = (15)^{2}$
$∴$ PN = 9 cm

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In the given figure, PQ is the tangent of the circle. Line segment PR intersects the circle at N and R. PQ = 15 cm, PR = 25 cm, find PN:

The correct option is C 9 cmPN×PR=(PQ2)PN×25=(15)2 ∴ PN = 9 cm

The correct option is C 9 cm
$P N \times P R = (P Q^{2}) P N \times 25 = (15)^{2}$
$∴$ PN = 9 cm