Question

In the given figure, $PQ\parallel RS$. If $\angle QPM={95}^o$ and $\angle PMR={30}^o$, then find $\angle MRS$

• A. ${90}^o$
• B. ${135}^o$
• C. ${125}^o$
• D. ${85}^o$

Answer 1

The correct option is C ${125}^o$

Extend $MR$ to meet $PQ$ at $x$.

In $△PMX,$

$\angle P+\angle M=\angle MXQ$

(using exterior angle property)

So, $\angle MXQ=95°+30°=125°$

and since $PQ\parallel SR,$

$\angle MRS=\angle RXQ=\angle MXQ=125°$