Question 16
In the given figure, PQ⊥RQ, PQ = 5 cm and QR = 5 cm. Then, △PQR is
a) a right-angled triangle but not isosceles
b) an isosceles right-angled triangle
c) isosceles but not a right-angled triangle
d) neither isosceles nor right-angled triangle
Given : PQ⊥RQ, PQ = 5 cm and QR = 5 cm
Since, PQ⊥RQ
So, ∠ PQR = 90∘
∴△ PQR is a right angled triangle.
Also, in △PQR,
PQ = QR
∴△ PQR is an isosceles triangle.
Hence, △ PQR is an isosceles right-angled triangle.