Question

Question 104

In the given figure, PQ || RT. Find the value of a+b.

Answer 1

Since, PQ || RT and RQ is transversal.
$Therefore,\angle TRQ=\angle RQP\left[alternateinteriorangles\right]\Rightarrow b={55}^{\circ }Also,\angle SRT=\angle SPQ\left[correspondingangles\right]\Rightarrow a={45}^{\circ }\therefore a+b={45}^{\circ }+{55}^{\circ }={100}^{\circ }$