Question

In the given figure; $PQR$ is a straight line. If $\angle SQR={75}^{\circ }$; find $\angle PQS$.

• A. 115°
• B. 105°
• C. 95°
• D. 125°

Answer 1

The correct option is B ($\angle 105°$)

Given, $PQR$ is a straight line.
So, $\angle PQS+\angle SQR={180}^{\circ }$
[as linear pair angles]
$\angle PQS+{75}^{\circ }={180}^{\circ }$
On further calculation, we get,
$\angle PQS=180–75$
$\therefore \angle PQS={105}^{\circ }$