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Question

In the given figure, prove that: [4 MARKS]



(i) ΔXYZΔXPZ

(ii) YZ = PZ

(iii) YXZ=PXZ

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Solution

Steps: 1 Mark
Each Proof: 1 Mark

(i) In ΔXYZ and ΔXPZ

XY=XP [Given]

XYZ=XPZ=90 [Given]

XZ=XZ [Common]

ΔXYZΔXPZ [RHS congruency criteria]

(ii) YZ=PZ [Corresponding parts of congruent triangles]

(iii) YXZ=PXZ [Corresponding parts of congruent triangles]

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