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Question

In the given figure, prove that:

(i) CD + DA + AB + BC > 2AC

(ii) CD + DA + AB > BC

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Solution

(1) We have to prove that

In we have

(As sum of two sides of triangle is greater than third one) ........(1)

In we have

(As sum of two sides of triangle is greater than third one) .........(2)

Hence

Adding (1) & (2) we get

Proved.

(2) We have to prove that

In we have

(As sum of two sides of triangle is greater than third one)

(Adding both sides)

Proved.


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