In the given figure, QA = AB = BC = CR. If ar(ΔPQR) = 24 cm2, then area(ΔPAR) is
18 cm2
All the triangles PQA, PBA, PBC, PCR are on equal base and between same parallels.
So, If area of each triangle is ‘x’
4x = 24, x = 6 cm2
So, Area of △PAR = 18 cm2