In the given figure, rays OA and OB stand on a line POQ. The value of $x$ is:

20^{o}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

25^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

35^{o}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $20^{o}$
Since ray OA stands on the line POQ, by Linear Pair Axiom we have
$∠ P O A + ∠ A O Q = 180^{o} \Rightarrow ∠ P O A + (∠ A O B + ∠ B O Q) = 180^{o} [∠ A O Q = ∠ A O B + ∠ B O Q] \Rightarrow 40^{o} + 4 x + 3 x = 180^{o} \Rightarrow 7 x = 140^{o} \Rightarrow x = 120^{o}$

Suggest Corrections

Similar questions

Q. In the given figure, ray OS stand on a line POQ, Ray OR and ray OT are angle bisectors of ∠POS and∠SOQ respectively. If ∠POS = x, find ∠ROT.

Q. In the given figure, rays OA, OB, OC and OD are such that
∠AOB = 56°, ∠BOC = 100°, ∠COD = x° and ∠DOA = 74°.
Find the value of x.

In the figure, ray OS stand on a line POQ. Ray OR and ray OT are angle bisectors of $∠ P O S$ and $∠ S O Q$ respectively. If $∠ P O S = x$ , find $∠ R O T$

Q. In the following figure, ray OS stands on a line POQ, ray OR and ray OT are angle bisectors of

∠

POS and

∠

QOS respectively.
If

∠

POS = x, find

∠

ROT.

In the figure below, ray OS stands on a line POQ. Ray OR and ray OT are angle bisectors of $∠$ POS and $∠$ SOQ, respectively. If $∠$ POS = $x$ , find $∠$ ROT.

Join BYJU'S Learning Program

In the given figure, rays OA and OB stand on a line POQ. The value of x is:

The correct option is A 20oSince ray OA stands on the line POQ, by Linear Pair Axiom we have ∠POA+∠AOQ=180o⇒∠POA+(∠AOB+∠BOQ)=180o [∠AOQ=∠AOB+∠BOQ]⇒40o+4x+3x=180o⇒7x=140o⇒x=120o

In the given figure, rays OA and OB stand on a line POQ. The value of $x$ is: