Question

In the given figure, rings A and B are moving along the rods at a given instant with velocities $V_1$ and $V_2$ respectively. PQ is vertical rod and rod RS is making an angle $\alpha$ with the vertical. Both rings are connected to an inextensible string which passes over the pulley. Which of the following option is correct :

• A. $V_{1}cos\theta =V_2$
• B. $V_{1}cos\alpha =V_2$
• C. $V_{2}cos(180-\alpha -\theta )=V_{1}cos\theta$
• D. $V_{2}sin\theta =V_{1}sin(\alpha +\theta )$

Answer 1

The correct option is A $V_{1}cos\theta =V_2$

we know that along a string all particles are having same speed.
From the fig we get, $V_{1}cos\theta =V_2$