In the given figure- S and T are the mid-points of sides PR and PQ respectively of - PQR- If ar - PQR - 48 cm2- then find ar - TSQ-

The correct option is B 12 cm^2 If area of PQR = 48c.m^2 If we consider QSP , then #160;area of this triangle is 24 c.m^2 because QS is ...

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Byju's Answer

Standard IX

Mathematics

Triangles between Same Parallels

In the given ...

Question

In the given figure, $S$ and $T$ are the mid-points of sides $P R$ and $P Q$ respectively of $Δ P Q R$ . If ar $(Δ P Q R) = 48 c m^{2}$ , then find ar $(Δ T S Q)$ .

48 c m^{2}

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24 c m^{2}

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12 c m^{2}

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6 c m^{2}

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Solution

The correct option is B $12 c m^{2}$
If area of $△ P Q R = 48 c . m^{2}$

If we consider $△ Q S P$ , then

area of this triangle is $24 c . m^{2}$

because QS is the median, median divide triangle in equal areas,

So, area of $△ Q S P = 24 c . m^{2}$

Now in $△ Q S P$ again 'ST' is median

So, area of $△ Q S T =$ half of $△ Q S P = \frac{1}{2} a r (△ Q S P)$

$∴ a r △ Q S T = 12 c . m^{2} \to$ option $-$ C

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In the given figure, S and T are the mid-points of sides PR and PQ respectively of ΔPQR. If ar (ΔPQR)=48cm2, then find ar (ΔTSQ).

In the given figure, $S$ and $T$ are the mid-points of sides $P R$ and $P Q$ respectively of $Δ P Q R$ . If ar $(Δ P Q R) = 48 c m^{2}$ , then find ar $(Δ T S Q)$ .