The correct option is C ∆ ABD ≅ ∆ EBC by AAS test
In the given figure, seg AD = seg EC,
Consider ∆ ABD and ∆ EBC,
∠ ADB = ∠ CEB (Alternate angles since AB ||EC )
∠ ABD = ∠ CBE (Vertically opposite angles)
& seg AD = seg EC (given)
Therefore, ∆ ABD ≅ ∆ EBC (AAS test).