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Question

In the given figure, seg AD = seg EC and AD || EC then


A
∆ ADB ≅ ∆ EBC by SAS test
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B
∆ ADB ≅ ∆ EBC by SAS test
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C
∆ ABD ≅ ∆ EBC by AAS test
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D
∆ ABD ≅ ∆ BEC by SSS test
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Solution

The correct option is C ∆ ABD ≅ ∆ EBC by AAS test
In the given figure, seg AD = seg EC,
Consider ∆ ABD and ∆ EBC,
∠ ADB = ∠ CEB (Alternate angles since AB ||EC )
∠ ABD = ∠ CBE (Vertically opposite angles)
& seg AD = seg EC (given)
Therefore, ∆ ABD ≅ ∆ EBC (AAS test).

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