CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the given figure, seg AD = seg EC and AD || EC then


A
∆ ADB ≅ ∆ EBC by SAS test
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
∆ ADB ≅ ∆ EBC by SAS test
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
∆ ABD ≅ ∆ EBC by AAS test
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
∆ ABD ≅ ∆ BEC by SSS test
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C ∆ ABD ≅ ∆ EBC by AAS test
In the given figure, seg AD = seg EC,
Consider ∆ ABD and ∆ EBC,
∠ ADB = ∠ CEB (Alternate angles since AB ||EC )
∠ ABD = ∠ CBE (Vertically opposite angles)
& seg AD = seg EC (given)
Therefore, ∆ ABD ≅ ∆ EBC (AAS test).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Special Parallelograms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon