Question

In the given figure, show that $\angle 1+\angle 3+\angle 8+\angle 6={360}^0$. [2 MARKS]

Answer 1

Proof: 2 Marks

$\angle 1+\angle 2+\angle 3+\angle 4={360}^0$ [Angles about a point]

$\angle 4=\angle 8$ [Pair of corresponding angles]

and $\angle 2=\angle 6$ [Pair of corresponding angles]

$\Rightarrow \angle 1+\angle 3+\angle 8+\angle 6={360}^0$