Question

In the given figure, side BC of $△ABC$ has been produced to D and CE || BA. If $\angle ABC={65}^o,$ $\angle BAC={55}^o,$ find $\angle ACE,$ and $\angle ECD$ respectively.

• A. ${65}^{o}and{55}^o$
• B.
  ${55}^{o}and{65}^o$
• C. ${45}^{o}and{30}^o$
• D. ${30}^{o}and{45}^o$

Answer 1

The correct option is B

${55}^{o}and{65}^o$
$\angle BAC-\angle ACE=$
$\angle ABC-\angle ECD=$
Given $\angle ABC={65}^o,\angle BAC={55}^o$
Corresponding angles,
$\angle ABC=\angle ECD={65}^o$
Alternate interior angles ,
$\angle BAC=\angle ACE={55}^o$