In the given figure, sides AB and AD of quad. ABCD are produced to E and F respectively. If ∠CBE = 100°, then ∠CDE = ?
(a) 100°
(b) 80°
(c) 130°
(d) 90°

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Solution

(b) 80°
In a cyclic quadrilateral ABCD, we have:
Interior opposite angle, ∠ADC = exterior ∠CBE = 100°
∴ ∠CDF = (180° - ∠ADC) = (180° - 100°) = 80° (Linear pair)

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In the given figure, sides AB and AD of quad. ABCD are produced to E and F respectively. If ∠CBE = 100°, then ∠CDE = ? (a) 100° (b) 80° (c) 130° (d) 90°

(b) 80° In a cyclic quadrilateral ABCD, we have: Interior opposite angle, ∠ADC = exterior ∠CBE = 100° ∴ ∠CDF = (180° - ∠ADC) = (180° - 100°) = 80° (Linear pair)

In the given figure, sides AB and AD of quad. ABCD are produced to E and F respectively. If ∠CBE = 100°, then ∠CDE = ?
(a) 100°
(b) 80°
(c) 130°
(d) 90°

(b) 80°
In a cyclic quadrilateral ABCD, we have:
Interior opposite angle, ∠ADC = exterior ∠CBE = 100°
∴ ∠CDF = (180° - ∠ADC) = (180° - 100°) = 80° (Linear pair)