1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# In the given figure,Suppose AB, AC and BC have lengths 10 cm, 11 cm and 12 cm respectively. If BDDC=56 and CEEA=310, then find AF and FB.

A
2 cm and 8 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8 cm and 2 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6 cm and 4 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5 cm and 5 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B 8 cm and 2 cmGiven that AB = 10 cm , AC = 11 cm and BC = 12 cm . Let AF = x cm and FB = y cm. Using Ceva’s theorem, we have, AFFB×CEEA×BDDC=1 ... (1) Substitute the values of BDDC=56 and CEEA=310 in (1), we have, 56×310×xy=1 xy×14=1 Hence, x = 4y ... (2) AB = AF + FB = 10 so, x + y = 10 ... (3) From (2), using x = 4y in (3), we get, 4y + y = 10 5y = 10 then y = 2 Substitute y = 2 in (3) we get, x = 8 . Hence AF = 8 cm , FB = 2 cm.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Construction
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program