In the given figure, T is a point on side QR of $Δ P Q R$ and S is a point such that RT = ST.
Which of the following is true?

PQ + PR < QS

No worries! We‘ve got your back. Try BYJU‘S free classes today!

PQ + PR > QS

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

PQ + TR > QS

No worries! We‘ve got your back. Try BYJU‘S free classes today!

PQ + TR < QS

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B PQ + PR > QS

Sum of the lengths of the two sides is always greater than the length of third side.

So in $Δ P Q R$ , we have
PQ + PR > QR
PQ + PR > QT + RT
[Since QR = QT + RT]

PQ + PR > QT + ST ... (i)
[Since RT = ST]

In $Δ Q S T$ , we have
QT + ST > QS ...(ii)

From (i) and (ii), we get
PQ + PR > QS

Suggest Corrections

Similar questions

In Fig. T is a point on side QR of $Δ P Q R$ and S is a point such that RT = ST. Which of the following is true?

In the given figure, RS = QT and QS = RT. Then which of the following options is correct?

In Fig. T is a point on side QR of △PQR and S is a point such that RT = ST. Prove that PQ + PR > QS

Join BYJU'S Learning Program