In the given figure,the angle between reflected ray is equal to:

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Solution

The correct option is B 2A
Since the rays are incident on the surface at angle $\frac{A}{2}$ , they will be reflected at the same angle from the surface.
By shifting the reflected rays parallel to the vertex of angle $A$ .
It is clear from the diagram that angle between reflected rays will be the sum o the angles made by reflected rays from the surface and the angle of the prism
$= A / 2 + A + A / 2 = 2 A$

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In the given figure, PQ is a mirror, AB is the incident ray and BC is the reflected ray. If $∠ A B C = 46^{\circ},$ then $∠ A B P$ is equal to

(a) $44^{\circ}$
(b) $67^{\circ}$
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(d) $62^{\circ}$

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A B

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∠ P Q R = 112^{o}

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∠ P O R = 112^{o}

find

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Q. In the figure given, AB is a mirror, PQ is the incident ray and QR, the reflected ray. If

∠

PQR

= 112^{o}

, find

∠

PQA.

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