Question

In the given figure, the area of the ruled portion is ____ $c{m}^2$.

• A. $616$
• B. $224$
• C. $196$
• D. $112$

Answer 1

The correct option is D $112$

The radius of the semi-circle is $\frac{28}{2}=14$ cm.

Now area of the semi-circle is $\frac{1}{2}\times \frac{22}{7}\times {14}^2=308$ cm${}^2$.

Now area of $\Delta AOC+\Delta BOC=2\times \frac{1}{2}\times 14\times 14=196$ cm${}^2$.

Now are of the ruled portion is $308-196=112$ cm${}^2$.