In the given figure, the arms of two angles are parallel to one another. If $∠ A B C = 70^{\circ}$ , then find $∠ D G C$

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110^{\circ}

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70^{\circ}

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90^{\circ}

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35^{\circ}

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Solution

The correct option is B $70^{\circ}$
AB ∥ DG
BC is the transversal line intersecting AB and DG
By the property of corresponding angles, $∠ D G C = ∠ A B C$
Then, $∠ D G C = 70^{\circ}$

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