In the given figure, the circle touches the sides AB, BC, CD and DA of a quadrilateral ABCD at the points P, Q, R, S respectively. If AB = 11 cm, BC =x cm, CR = 4 cm and AS = 6 cm, the value of x is
AP = AS = 6 cm
BP = BA – AP = 11 – 6 = 5
BQ = BP = 5
CQ = CR = 4
x = CQ + BQ
x = 4 + 5 = 9 cm