Question

In the given figure the current in $5\Omega$ resistance is k ampere. Find the value of k.

• A. 8A
• B. 9A
• C. 6A
• D. 2A

Answer 1

The correct option is C 6A

$I=\frac{V}{R}$

$\therefore I_1=\frac{60+20}{40}=2A$

$\therefore I_2=\frac{50-10}{20}=2A$

$\therefore I_3=\frac{80}{40}=2A$

$\therefore I_4=\frac{40}{10}=4A$

$\therefore I_5=\frac{20}{5}=4A$

Net current flowing through $5\Omega$ resistor.

$=(I_1+I_2+I_3+I_4)=I_5$

$(2+2+2+4)-4$

$6A$