In the given figure the current through the 20 V battery is:

11 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7 A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

14 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 7 A
R.E.F image
Hence by cell method
$I = \frac{\in e q}{R + r}$
$= \frac{16 + 16 + 20}{0 + (4 + 2)} = \frac{42}{6}$
$= 7 A$

Suggest Corrections

Similar questions

a_{1}, a_{2}, a_{3}, . . . . . . . ., a_{25}

a_{3} + a_{5} + a_{12} + a_{14} + a_{21} + a_{23} = 60

a_{2} + a_{7} + a_{19} + a_{24} =

Three resistors are connected to a 12 V battery as shown in the figure given below:

The current through the 6 ohm resistor is:

20 Ω

12 V

Join BYJU'S Learning Program