wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the given figure the flux through the loop perpendicular to the plane of the coil and directed into the paper is varying according to the relation ϕ=6t2+7t+1, where ϕ is in milliweber and t is in second. The magnitude of the emf induced in the loop at t=2s and the direction of induce current through R are

206711.png

A
39 mV; right to left
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
39 mV; left to right
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
31 mV; right to left
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
31 mV; left to right
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 31 mV; left to right
ϕ=6t2+7t+1dϕdt=12t+7
At time, t=2 s.
dϕdt=24+7=31 volt
Direction of current is from left to right according to Lenz'a law and the Flemmings right hand rule.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Direction of Induced Current
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon