In the given figure, the focal length of the two mirrors $M - 1$ and $M - 2$ for the given incident rays are $f_{1}$ and $f_{2}$ respectively, then

f_{1} = + v e, f_{2} = + v e

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f_{1} = - v e, f_{2} = - v e

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f_{1} = + v e, f_{2} = - v e

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f_{1} = - v e, f_{2} = + v e

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Solution

The correct option is D $f_{1} = - v e, f_{2} = + v e$
The direction of incident ray is taken as positive.
Also, all distance are measured from pole.
So, $f_{1} = - v e & f_{2} = + v e$

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