Question

In the given figure, the measure of $\angle BAC$ is

• A. ${65}^o$
• B. ${50}^o$
• C. ${55}^o$
• D. ${60}^o$

Answer 1

Answer: (B)

${50}^o$

In $△ABC$ using angle sum property

$\angle A+\angle B+\angle C={180}^{\circ }$

$\angle A+{65}^{\circ }+{65}^{\circ }={180}^{\circ }$

$\angle A={180}^{\circ }-{130}^{\circ }$

$\angle A={50}^{\circ }$