In the given figure the measure of ∠D and ∠F are respectively

(a) 50°, 40°
(b) 20°, 30°
(c) 40°, 50°
(d) 30°, 20°

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Solution

ΔABC and ΔDEF,

$\frac{AB}{AC} = \frac{EF}{ED} ∠ A = ∠ E = 130 °$

ΔABC $~$ ΔEFD (SAS Similarity)

$∴ ∠ F = ∠ B = 30 ° ∠ D = ∠ C = 20 °$

Hence the correct answer is

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In the given figure the measure of ∠D and ∠F are respectively (a) 50°, 40° (b) 20°, 30° (c) 40°, 50° (d) 30°, 20°

ΔABC and ΔDEF, ABAC=EFED∠A=∠E=130° ΔABC ~ ΔEFD (SAS Similarity) ∴∠F=∠B=30°∠D=∠C=20° Hence the correct answer is

In the given figure the measure of ∠D and ∠F are respectively

(a) 50°, 40°
(b) 20°, 30°
(c) 40°, 50°
(d) 30°, 20°

ΔABC and ΔDEF,

$\frac{AB}{AC} = \frac{EF}{ED} ∠ A = ∠ E = 130 °$

ΔABC $~$ ΔEFD (SAS Similarity)

$∴ ∠ F = ∠ B = 30 ° ∠ D = ∠ C = 20 °$

Hence the correct answer is