Find the value of - AOB-A- 90-B- 60-C- 120-D- 110-

The correct option is A 90^∘ The ratio of ∠2 : ∠1 = 2 : 1 2x + x = 180^∘ 3x=180^∘ x=60^∘ ∠ 1=60^∘ In ΔAOB, 180^∘=30^∘+60^∘+ ∠ AOB ∠AOB = 180^∘ 90^∘ =90^∘ ...

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Byju's Answer

Standard IX

Mathematics

Alternatives of Postulate 5

Find the valu...

Question

In the given figure, the ratio of $∠$ 2 : $∠$ 1 = 2 : 1. Find the value of $∠$ AOB.

$60^{\circ}$

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$90^{\circ}$

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$120^{\circ}$

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$110^{\circ}$

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Solution

The correct option is B
$90^{\circ}$

The ratio of $∠$ 2 : $∠$ 1 = 2 : 1
2x + x = $180^{\circ}$
$3 x = 180^{\circ}$
$x = 60^{\circ}$
$∠ 1 = 60^{\circ}$
In $Δ$ AOB, $180^{\circ} = 30^{\circ} + 60^{\circ} + ∠ A O B$
$∠$ AOB = $180^{\circ} - 90^{\circ}$
$= 90^{\circ}$

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In the given figure, the ratio of ∠2 : ∠1 = 2 : 1. Find the value of ∠AOB.

The correct option is B 90∘ The ratio of ∠2 : ∠1 = 2 : 1 2x + x = 180∘ 3x=180∘ x=60∘ ∠1=60∘ In ΔAOB, 180∘=30∘+60∘+∠AOB ∠AOB = 180∘−90∘ =90∘

In the given figure, the ratio of $∠$ 2 : $∠$ 1 = 2 : 1. Find the value of $∠$ AOB.

The correct option is B
$90^{\circ}$

The ratio of $∠$ 2 : $∠$ 1 = 2 : 1
2x + x = $180^{\circ}$
$3 x = 180^{\circ}$
$x = 60^{\circ}$
$∠ 1 = 60^{\circ}$
In $Δ$ AOB, $180^{\circ} = 30^{\circ} + 60^{\circ} + ∠ A O B$
$∠$ AOB = $180^{\circ} - 90^{\circ}$
$= 90^{\circ}$