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Byju's Answer

Standard XII

Physics

Introduction to Radial & Tangential Acceleration

In the given ...

Question

In the given figure, the sphere rolls without slipping on the plank which is moving with constant velocity $v_{0}$ . The radius and angular velocity of the sphere is r and $ω$ respectively. The velocity of centre of mass of the sphere is :

v_{0}

+ r

ω

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v_{0}

- r

ω

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ω

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v_{0}

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Solution

The correct option is A $v_{0}$ + r $ω$
For pure rolling,
$v_{0} = v_{c m} - r ω \Rightarrow v_{c m} = v_{0} + r ω$

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In the given figure, the sphere rolls without slipping on the plank which is moving with constant velocity v0. The radius and angular velocity of the sphere is r and ω respectively. The velocity of centre of mass of the sphere is :

The correct option is A v0 + r ωFor pure rolling, v0=vcm−rω⇒vcm=v0+rω

In the given figure, the sphere rolls without slipping on the plank which is moving with constant velocity $v_{0}$ . The radius and angular velocity of the sphere is r and $ω$ respectively. The velocity of centre of mass of the sphere is :

The correct option is A $v_{0}$ + r $ω$
For pure rolling,
$v_{0} = v_{c m} - r ω \Rightarrow v_{c m} = v_{0} + r ω$