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Trigonometric Ratios of Common Angles

In the given ...

Question

In the given figure , the value of cosec A is

\frac{5}{12}

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\frac{12}{13}

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\frac{5}{13}

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\frac{13}{12}

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Solution

The correct option is D $\frac{13}{12}$
$c o s e c A = \frac{h}{p}$
$h = A C = \sqrt{12^{2} + 5^{2}} = 13$
$c o s e c A = \frac{13}{12}$

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In figure, AC = 13 cm, BC = 12 cm, then sec θ equals :

Δ A B C

5 \times s i n A = 3

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