Question 9In the given figure- the value of x isa 110-b 46-c 64-d 150-

The correct option is ∴ 100^∘+46^∘ +64^∘ +x = 360^∘ ⇒ 210^∘ + x = 360^∘ ⇒ x = 360^∘ 210^∘ ⇒ x = 150^∘ ...

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Standard VII

Mathematics

Perpendicular Bisector

Question 9In ...

Question

Question 9
In the given figure, the value of x is

(a) $110^{\circ}$
(b) $46^{\circ}$
(c) $64^{\circ}$
(d) $150^{\circ}$

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Solution

$∴ 100^{\circ} + 46^{\circ} + 64^{\circ} + x = 360^{\circ} \Rightarrow 210^{\circ} + x = 360^{\circ} \Rightarrow x = 360^{\circ} - 210^{\circ} \Rightarrow x = 150^{\circ}$

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Question 9 In the given figure, the value of x is (a) 110∘ (b) 46∘ (c) 64∘ (d) 150∘

∴100∘+46∘+64∘+x=360∘⇒210∘+x=360∘⇒x=360∘−210∘⇒x=150∘

Question 9
In the given figure, the value of x is

(a) $110^{\circ}$
(b) $46^{\circ}$
(c) $64^{\circ}$
(d) $150^{\circ}$

$∴ 100^{\circ} + 46^{\circ} + 64^{\circ} + x = 360^{\circ} \Rightarrow 210^{\circ} + x = 360^{\circ} \Rightarrow x = 360^{\circ} - 210^{\circ} \Rightarrow x = 150^{\circ}$