In the given figure, there are two circles with the centres O and O' touching each other internally at P. Tangents TQ and TP are drawn to the larger circle and tangents TP and TR are drawn to the smaller circle . Find TQ : TR
1 : 1
As the lengths of tangents drawn from an external point to a circle are equal,
For the circle with center O, TQ = TP ….(i)
For the circle with center O′, TR = TP ….(ii)
Dividing equation (i) by (ii), we get,
TQ : TR = 1 : 1