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Question

In the given figure there are two concentric circles. PQ is a chord of the outer circle which touches the inner circle at point L. Select the correct option from the following.

A
PL > QL
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B
PL < QL
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C
PL = QL
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D
PL = 2 × QL
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Solution

The correct option is C PL = QL
By Theorem: In two concentric circles, the chord of the bigger circle, that touches the smaller circle is bisected at the point of contact with the smaller circle.
so, PL = QL

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Chord of the Bigger Circle Is Bisected at the Point of Contact with the Smaller Circle
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