Properties of Angles Formed by Two Parallel Lines and a Transversal
In the given ...
Question
In the given figure, Tr || VS, TU || RS, ∠RPQ is twice of ∠UVS, then find a + b
A
165∘
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B
185∘
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C
225∘
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D
155∘
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Solution
The correct option is D155∘ In the given figure, Tr || VS, TU || RS, RPQ is twice of UVS Then ∠RPQ=2∠UVS=2(25)=500 TU||RS then ∠UTQ=∠SRQ=900 And ∠QRP=180-∠SRQ=180-90=900 IN triangle PQR ∠a=180-∠QRP-∠RPQ=180-90-50=400 TR||VS Then ∠b=∠RTV+∠UVS=90+25=1150 Then a+b=40+115=1550