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Question

In the given figure, ABC is an isosceles triangle in which AB=AC. If BDAC and CEAB, prove that BD=CE.
1305921_a006614d9eb046ce8a3bedb1ef75e659.png

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Solution

Given:

ΔABC is isosceles triangle.

and, AB=AC

BDAC&CEAB

To prove:

BD=CE

Proof:


In ΔBEC&ΔCDB, we have

BEC=CDB=90 [BD and CD are altitudes]

EBC=DCB [AB=AC, angles opposite to equal sides are equal]

BC=CB [Common in both triangles]

ΔBECΔCDB ( by AAS congruence Rule)

Hence, BD=CE (by CPCT)

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