In the given figure, △ABC is an isosceles triangle in which AB=AC. If BD⊥AC and CE⊥AB, prove that BD=CE.
Given:
ΔABC is isosceles triangle.
and, AB=AC
BD⊥AC&CE⊥AB
To prove:
BD=CE
Proof:
In ΔBEC&ΔCDB, we have
∠BEC=∠CDB=90∘ [BD and CD are altitudes]
∠EBC=∠DCB [∵AB=AC, angles opposite to equal sides are equal]
BC=CB [Common in both triangles]
ΔBEC≅ΔCDB ( by AAS congruence Rule)